lemasquegris: (elvi_steech)
[personal profile] lemasquegris
Here everyone, a little mathalchemy. ;)
(for question 5, they mean as of this year)

CHOCOLATE MATH

Be sure you don't read the bottom until you've worked it out.

1. First of all, pick the number of times a week that you would like to have the chocolate (more than once but less than 10)

2. Multiply this number by 2

3. Add 5

4. Multiply it by 50 -- I'll wait while you get the calculator.

5. If you have already had your birthday this year add 1756 .... If you haven't, add 1755.

6. Now subtract the four digit year that you were born.

You should have a three digit number.

The first digit of this was your original number (i.e., how many times you want to have the chocolate each week).

The next two numbers are...your age. :D

Date: 2006-04-17 07:15 pm (UTC)
From: [identity profile] centesis.livejournal.com

Nice bit of math.Where did you find that?

Date: 2006-04-17 10:38 pm (UTC)
From: [identity profile] netik.livejournal.com
This is nothing special, aside from showing the distributive and commutive properties of basic algebra:

The 1st operation shifts the "chocolate" value to the hundreds column. The addition of 5 is there to throw you off:

y = (2n + 5) * 50
y = 100n + 250

The second operation is basic math, with the constants:

250 + 1756 (or 1755, depending) = 2006 (oh look, that's this year !)

And then;

2006 - your birth year = your age.


Nothing special, really, but fun if you don't pay attention to the numbers.



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